Pickle Problem¶
Given a Series called pickle
, replace NaN
s using the following algorithm.
for each NaN:
get the nearest non NaN value before and after it
if both of those values exist:
replace NaN with the minimum of those two non NaN values
else:
replace NaN with the nearest non NaN value
import numpy as np
import pandas as pd
pickle = pd.Series([1.5, np.nan, 2.3, np.nan, np.nan, -3.9, np.nan, 4.5, np.nan, np.nan, np.nan, 1.9, np.nan])
print(pickle)
# 0 1.5
# 1 NaN
# 2 2.3
# 3 NaN
# 4 NaN
# 5 -3.9
# 6 NaN
# 7 4.5
# 8 NaN
# 9 NaN
# 10 NaN
# 11 1.9
# 12 NaN
# dtype: float64